GATE CSE 2020 Q30: Decoder inputs plus outputs for a byte-addressable 1 KB RAM

Digital Logic
1 mark
NAT
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If there are $m$ input lines and $n$ output lines for a decoder that is used to uniquely address a byte addressable 1 KB RAM, then the minimum value of $m + n$ is ____.

Try it: numerical answer: type the value

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Numerical answer. No negative marking.

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Answer: 1034 (official GATE 2020 final answer key)

Concept used: An $m$ -to- $2^m$ decoder selects one of $2^m$ locations.

First step: 1 KB byte-addressable means 1024 locations, so $m = 10$ and $n = 2^{10}$ .

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Source: official GATE 2020 CS question paper and final answer key, organised by IIT Delhi. Question paper · Answer key

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GATE CSE 2020 Q30: Decoder inputs plus outputs for a byte-addressable 1 KB RAM

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