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GATE CSE 2026 Session 2 Q27: Definite integral I(a) of 3x² − ax + 1 over [−1, 1]

Question

For a real number aa, let I(a)=∫−11(3x2−ax+1) dxI(a) = \displaystyle\int_{-1}^{1} (3x^2 - ax + 1)\, dx. Which of the following statements is/are true?

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Answer: A, C (official GATE 2026 final answer key)

Concept used: The integral of an odd function over a symmetric interval is zero.

First step: The term −ax-ax is odd, so it integrates to 0 over [−1,1][-1, 1]; integrate 3x2+13x^2 + 1.

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Source: official GATE 2026 Session 2 CS question paper and final answer key, organised by IIT Guwahati. Question paper · Answer key