Skip to content
GATEiit

GATE DA 2024 Q24: False conditional independence in a factorised distribution

Question

Consider five random variables U,V,W,XU, V, W, X, and YY whose joint distribution satisfies:

P(U,V,W,X,Y)=P(U)P(V)P(W∣U,V)P(X∣W)P(Y∣W)P(U, V, W, X, Y) = P(U)P(V)P(W \mid U, V)P(X \mid W)P(Y \mid W)

Which ONE of the following statements is FALSE?

Try it: multiple choice: exactly one correct option

Select one option
Wrong answer costs 1/3 mark in GATE.
Show answer and explanation

Answer: C (official GATE 2024 final answer key)

Concept used: d-separation in Bayesian networks; observing a common child (collider) makes its parents dependent.

First step: The network is U→W←VU \to W \leftarrow V, W→XW \to X, W→YW \to Y; WW is a collider for UU and VV.

Full step-by-step solution

Detailed working, common mistakes and linked mock tests will be available with a free GATEiit account. Log-in is coming soon.

Share this question

WhatsAppDownload image

Source: official GATE 2024 DA question paper and final answer key, organised by IISc Bangalore. Question paper · Answer key