Skip to content
GATEiit

GATE CSE 2024 Session 2 Q55: Minimum Ethernet frame size for collision detection

Question

Consider an Ethernet segment with a transmission speed of 10810^8 bits/sec and a maximum segment length of 500 meters. If the speed of propagation of the signal in the medium is 2×1082 \times 10^8 meters/sec, then the minimum frame size (in bits) required for collision detection is _________

Try it: numerical answer: type the value

Numerical answer. No negative marking.
Show answer and explanation

Answer: 500 (official GATE 2024 final answer key)

Concept used: CSMA/CD: transmission time must be at least the round-trip propagation time.

First step: One-way propagation is 500/(2×108)=2.5 μs500 / (2 \times 10^8) = 2.5\ \mu s; the frame must last 2×2.5 μs2 \times 2.5\ \mu s at 10810^8 bits/s.

Full step-by-step solution

Detailed working, common mistakes and linked mock tests will be available with a free GATEiit account. Log-in is coming soon.

Share this question

WhatsAppDownload image

Source: official GATE 2024 Session 2 CS question paper and final answer key, organised by IISc Bangalore. Question paper · Answer key

More Computer Networks PYQs

PracticePractise Computer Networks questions →Full paperAll GATE CSE 2024 Session 2 questions →